Search: id:A000182 Results 1-1 of 1 results found. %I A000182 M2096 N0829 %S A000182 1,2,16,272,7936,353792,22368256,1903757312,209865342976, %T A000182 29088885112832,4951498053124096,1015423886506852352,246921480190207983616, %U A000182 70251601603943959887872,23119184187809597841473536 %N A000182 Tangent (or "Zag") numbers: expansion of tan x. Also expansion of tanh(x). %C A000182 Number of Joyce trees with 2n-1 nodes. Number of tremolo permutations of {0,1,...,2n}. - Ralf Stephan (ralf(AT)ark.in-berlin.de), Mar 28 2003 %C A000182 The Hankel transform of this sequence is A000178(n) for n odd = 1, 12, 34560, ...; example : det([1, 2, 16; 2, 16, 272, 16, 272, 7936]) = 34560 . - DELEHAM Philippe (kolotoko(AT)wanadoo.fr), Mar 07 2004 %C A000182 a(n) = number of increasing labeled full binary trees with 2n-1 vertices. Full binary means every non-leaf vertex has two children, distinguished as left and right; labeled means the vertices are labeled 1,2,..., 2n-1; increasing means every child has a label greater than its parent. - David Callan (callan(AT)stat.wisc.edu), Nov 29 2007 %C A000182 Contribution from Micha Hofri (hofri(AT)wpi.edu), May 27 2009: (Start) %C A000182 a(n) was found to be the number of permutations of [2n] which when inserted in %C A000182 order, to form a binary search tree, yield the maximally full possible tree (with only one single-child node). %C A000182 The egf is sec^2(x)=1+tan^2(x), and the same coefficients can be manufactured from the tan(x) itself, %C A000182 which is the egf for the number of trees as above for odd number of nodes. (End) %D A000182 L. Comtet, Advanced Combinatorics, Reidel, 1974, p. 88. %D A000182 H. Doerrie, 100 Great Problems of Elementary Mathematics, Dover, NY, 1965, p. 69. %D A000182 D. Dumont, Interpretations combinatoires des nombres de Genocchi, Duke Math. J., 41 (1974), 305-318. %D A000182 Dominique Foata and Guo-Niu Han, Dimers and new q-tangent numbers, Preprint, 2008. %D A000182 Ghislain R. Franssens, On a Number Pyramid Related to the Binomial, Deleham, Eulerian, MacMahon and Stirling number triangles, Journal of Integer Sequences, Vol. 9 (2006), Article 06.4.1. %D A000182 Knuth, D. E.; Buckholtz, Thomas J.; Computation of tangent, Euler and Bernoulli numbers. Math. Comp. 21 1967 663-688. %D A000182 L. M. Milne-Thompson, Calculus of Finite Differences, 1951, p. 148 (the numbers |C^{2n-1}| ). %D A000182 J. W. Milnor and J. D. Stasheff, Characteristic Classes, Princeton, 1974, p. 282. %D A000182 S. Mukai, An Introduction to Invariants and Moduli, Cambridge, 2003; see p. 444. %D A000182 H. Rademacher, Topics in Analytic Number Theory, Springer, 1973, Chap. 1, p. 20. %D A000182 D. Shanks, Generalized Euler and class numbers, Math. Comp. 21 (1967), 689-694; 22 (1968), 699. %D A000182 N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence). %D A000182 N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence). %H A000182 N. J. A. Sloane, The first 100 tangent numbers: Table of n, a(n) for n = 1..100 %H A000182 J. L. Arregui, Tangent and Bernoulli numbers related to Motzkin and Catalan numbers by means of numerical triangles. %H A000182 F. C. S. Brown, T. M. A. Fink and K. Willbrand, On arithmetic and asymptotic properties of up-down numbers %H A000182 K.-W. Chen, Algorithms for Bernoulli numbers and Euler numbers, J. Integer Sequences, 4 (2001), #01.1.6. %H A000182 P. Flajolet and R. Sedgewick, Analytic Combinatorics, 2009; see page 144 %H A000182 M.-P. Grosset and A. P. Veselov, Bernoulli numbers and solitons %H A000182 A. R. Kr\"auter, Permanenten - Ein kurzer \"Uberblick %H A000182 A. R. Kr\"auter, \"Uber die Permanente gewisser zirkul\"arer Matrizen... %H A000182 N. E. Noerlund, Vorlesungen ueber Differenzenrechnung Springer 1924, p. 27. %H A000182 N. J. A. Sloane, My favorite integer sequences, in Sequences and their Applications (Proceedings of SETA '98). %H A000182 R. Street, [math/0303267] Trees, permutations and the tangent function. %H A000182 Ross Street, Trees, permutations and the tangent function gives definition of Joyce trees and tremolo permutations. %H A000182 Eric Weisstein's World of Mathematics, Link to a section of The World of Mathematics. %H A000182 Eric Weisstein's World of Mathematics, Alternating Permutation %H A000182 Index entries for "core" sequences %H A000182 Index entries for sequences related to boustrophedon transform %H A000182 Index entries for sequences related to Bernoulli numbers. %F A000182 E.g.f.: log(sec x) = Sum_{n > 0} a(n)*x^(2*n)/(2*n)!. %F A000182 E.g.f.: tan x = Sum_{n >= 0} a(n+1)*x^(2*n+1)/(2*n+1)!. %F A000182 E.g.f.: (sec x)^2 = Sum_{n >= 0} a(n+1)*x^(2*n)/(2*n)!. %F A000182 2/(exp(2x)+1) = 1 + Sum_{n>=1} (-1)^(n+1) a(n) x^(2n-1)/(2n-1)! = 1 - x + x^3/3 - 2*x^5/15 + 17*x^7/315 - 62*x^9/2835 + ... %F A000182 a(n) = 2^(2*n) (2^(2*n) - 1) |B_(2*n)| / (2*n) where B_n are the Bernoulli numbers (A000367/A002445 or A027641/A027642). %F A000182 Asymptotics: a(n) ~ 2^(2*n+1)*(2*n-1)!/Pi^(2*n). %F A000182 Sum[2^(2*n + 1 - k)*(-1)^(n + k + 1)*k!*StirlingS2[2*n + 1, k], {k, 1, 2*n + 1}]. - Victor Adamchik, Oct 05 2005 %F A000182 a(n) = abs[c(2*n-1)] where c(n)= 2^(n+1) * (1-2^(n+1)) * Ber(n+1)/(n+1) = 2^(n+1) * (1-2^(n+1)) * (-1)^n * Zeta(-n) = [ -(1+EN(.))]^n = 2^n * GN(n+1)/(n+1) = 2^n * EP(n,0) = (-1)^n * E(n,-1) = (-2)^n * n! * Lag[n,-P(.,-1)/2] umbrally = (-2)^n * n! * C{T[.,P(.,-1)/2] + n, n} umbrally for the signed Euler numbers EN(n), the Bernoulli numbers Ber(n), the Genocchi numbers GN(n), the Euler polynomials EP(n,t), the Eulerian polynomials E(n,t), the Touchard / Bell polynomials T(n,t), the binomial function C(x,y) = x!/[(x-y)!*y! ] and the polynomials P(j,t) of A131758. - Tom Copeland (tcjpn(AT)msn.com), Oct 05 2007 %F A000182 Contribution from Johannes W. Meijer (meijgia(AT)hotmail.com), Jun 27 2009: (Start) %F A000182 a(1) = A094665(0,0)*A156919(0,0) and a(n) = sum(2^(n-k-1)*A094665(n-1, k)*A156919(k,0), k = 1..n-1) for n = 2, 3, .. , see A162005. %F A000182 (End) %e A000182 tan(x) = x + 2 x^3/3! + 16 x^5/5! + 272 x^7/7! + ... = x+1/3*x^3+2/15*x^5+17/ 315*x^7+62/2835*x^9+O(x^11). %e A000182 tanh(x) = x-1/3*x^3+2/15*x^5-17/315*x^7+62/2835*x^9-1382/155925*x^11+... %e A000182 (sec x)^2 = 1 + x^2 + 2/3*x^4 + 17/45*x^6 + ... %p A000182 series(tan(x),x,40); %p A000182 with(numtheory): a := n-> abs(2^(2*n)*(2^(2*n)-1)*bernoulli(2*n)/(2*n)); %t A000182 Table[ Sum[2^(2*n + 1 - k)*(-1)^(n + k + 1)*k!*StirlingS2[2*n + 1, k], {k, 1, 2*n + 1}], {n, 0, 7}] - Victor Adamchik, Oct 05 2005 %t A000182 v[1] = 2; v[n_] /; n >= 2 := v[n] = Sum[ Binomial[2 n - 3, 2 k - 2] v[k] v[n - k], {k, n - 1}]; Table[ v[n]/2, {n, 15}] [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Jul 08 2009] %o A000182 (PARI) a(n)=if(n<1,0,((-4)^n-(-16)^n)*bernfrac(2*n)/2/n) %o A000182 (PARI) a(n)=local(an);if(n<1,n>=0,an=vector(n+1,m,1);for(m=1,n,an[m+1]=sum(k=0, m-1,binomial(2*m,2*k+1)*an[k+1]*an[m-k]));an[n+1]) (from Michael Somos) %o A000182 (PARI) a(n)=if(n<0,0,(2*n+1)!*polcoeff(tan(x+O(x^(2*n+2))),2*n+1)) (from Michael Somos) %Y A000182 a(n)=2^(n-1)*A002105(n). Apart from signs, 2^(2n-2)*A001469(n) = n*a(n). %Y A000182 Cf. A001469, A002430, A036279, A000364 (secant numbers), A000111 (secant-tangent numbers), A024283, A009764. First diagonal of A059419 and of A064190. %Y A000182 Cf. A009006, A009725, A029584, A012509, A009123, A009567. %Y A000182 Equals A002425(n) * 2^A101921(n). %Y A000182 Contribution from Johannes W. Meijer (meijgia(AT)hotmail.com), Jun 27 2009: (Start) %Y A000182 Equals first left hand column of A162005. %Y A000182 (End) %Y A000182 Sequence in context: A050974 A012188 A009764 this_sequence A102599 A123744 A136796 %Y A000182 Adjacent sequences: A000179 A000180 A000181 this_sequence A000183 A000184 A000185 %K A000182 nonn,core,easy,nice %O A000182 1,2 %A A000182 N. J. A. Sloane (njas(AT)research.att.com). Search completed in 0.002 seconds