|
Search: id:A000302
|
|
|
| A000302 |
|
Powers of 4. (Formerly M3518 N1428)
|
|
+0 155
|
|
| 1, 4, 16, 64, 256, 1024, 4096, 16384, 65536, 262144, 1048576, 4194304, 16777216, 67108864, 268435456, 1073741824, 4294967296, 17179869184, 68719476736, 274877906944, 1099511627776, 4398046511104, 17592186044416, 70368744177664, 281474976710656
(list; graph; listen)
|
|
|
OFFSET
|
0,2
|
|
|
COMMENT
|
Same as Pisot sequences E(1,4), L(1,4), P(1,4), T(1,4). See A008776 for definitions of Pisot sequences.
The convolution square root of this sequence is A000984, the central binomial coefficients: C(2n,n). - T. D. Noe (noe(AT)sspectra.com), Jun 11 2002
a(n)=sum(k=0,n,C(2k,k)*C(2(n-k),n-k)). - Benoit Cloitre (benoit7848c(AT)orange.fr), Jan 26 2003
With p(n) = the number of integer partitions of n, p(i) = the number of parts of the i-th partition of n, d(i) = the number of different parts of the i-th partition of n, m(i,j) = multiplicity of the j-th part of the i-th partition of n, sum_{i=1}^{p(n)} = sum over i and prod_{j=1}^{d(i)} = product over j one has: a(n)=sum_{i=1}^{p(n)} p(i)!/(prod_{j=1}^{d(i)} m(i,j)!) * 2^(n-1) - Thomas Wieder (wieder.thomas(AT)t-online.de), May 18 2005
Sums of rows of the triangle in A122366. - Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Aug 30 2006
A000005(a(n)) = A005408(n+1). - Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Mar 04 2007
Number of n-permutations (n=1) of 5 objects u,v,w z x, with repetition allowed, containing exactly null u (or free). Example: a(1)=4 because we have v, w, z, x. - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), May 19 2008
Hankel transform of A076035. [From Philippe DELEHAM (kolotoko(AT)wanadoo.fr), Feb 28 2009]
Equals the Catalan sequence: (1, 1, 2, 5, 14,...), convolved with A032443: (1, 3, 11, 42,...). [From Gary W. Adamson (qntmpkt(AT)yahoo.com), May 15 2009]
A160700(a(n)) = A010685(n). [From Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Jun 10 2009]
Numbers n such that n^3+(2n)^3+(3n)^3=36*n^3 is square [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Aug 05 2009]
|
|
REFERENCES
|
N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence).
N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence).
|
|
LINKS
|
T. D. Noe, Table of n, a(n) for n = 0..100
P. J. Cameron, Sequences realized by oligomorphic permutation groups, J. Integ. Seqs. Vol. 3 (2000), #00.1.5.
INRIA Algorithms Project, Encyclopedia of Combinatorial Structures 8
INRIA Algorithms Project, Encyclopedia of Combinatorial Structures 269
Tanya Khovanova, Recursive Sequences
S. Plouffe, Approximations de S\'{e}ries G\'{e}n\'{e}ratrices et Quelques Conjectures, Dissertation, Universit\'{e} du Qu\'{e}bec \`{a} Montr\'{e}al, 1992.
S. Plouffe, 1031 Generating Functions and Conjectures, Universit\'{e} du Qu\'{e}bec \`{a} Montr\'{e}al, 1992.
Y. Puri and T. Ward, Arithmetic and growth of periodic orbits, J. Integer Seqs., Vol. 4 (2001), #01.2.1.
Eric Weisstein's World of Mathematics, Cantor Dust
Index entries for "core" sequences
Index entries for sequences related to linear recurrences with constant coefficients
|
|
FORMULA
|
a(n) = 4^n; a(n) = 4a(n-1).
G.f.: 1/(1-4x), e.g.f.: exp(4x)
1 = Sum(n = 1 through infinity) 3/a(n) = 3/4 + 3/16 + 3/64 + 3/256 + 3/1024...; with partial sums: 3/4, 15/16, 63/64, 255/256, 1023/1024... - Gary W. Adamson (qntmpkt(AT)yahoo.com), Jun 16 2003
a(n)=A001045(2n)+A001045(2n+1). - Paul Barry (pbarry(AT)wit.ie), Apr 27 2004
a(n)=sum(2^(n-j)*binomial(n+j,j),j=0..n) - Peter C. Heinig (algorithms(AT)gmx.de), Apr 06 2007
Hankel transform of A115967 . - Philippe DELEHAM (kolotoko(AT)wanadoo.fr), Jun 22 2007
a(n) = 6*StirlingS2(n+1,4) + 6*StirlingS2(n+1,3) + 3*StirlingS2(n+1,2) + 1 = 2*StirlingS2(2^n,2^n - 1) + StirlingS2(n+1,2) + 1. - Ross La Haye (rlahaye(AT)new.rr.com), Jun 26 2008
((2+sqrt4)^n-(2-sqrt4)^n)/4 in Fibonacci form. Offset 1. a(3)=16. [From Al Hakanson (hawkuu(AT)gmail.com), Dec 31 2008]
|
|
EXAMPLE
|
1^3+2^3+3^3=36=6^2; 4^3+8^3+12^3=2304=48^2; 16^3+32^3+48^3=147456=384^2 [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Aug 05 2009]
|
|
MAPLE
|
A000302 := n->4^n;
for n from 1 to 10 do sum(2^(n-j)*binomial(n+j, j), j=0..n); od; - Peter C. Heinig (algorithms(AT)gmx.de), Apr 06 2007
A000302:=-1/(-1+4*z); [S. Plouffe in his 1992 dissertation.]
seq(binomial(n+0, 0)*4^n, n=0..24); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), May 19 2008
with(finance):seq(mul(cashflows([1, 1, 2], 0 ), k=1..n), n=0..36); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Jul 02 2008
a:=n->mul(3+mul(1, j=2..n), j=1..n):seq(a(n), n=0..26); # [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Dec 06 2008]
g:=(1+2*z)/(1-4*z): gser:=series(g, z=0, 43): seq((coeff(gser, z, n))/6, n=1..24); # [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Feb 25 2009]
with(finance):seq(futurevalue(1, 3, n), n=0..24); # [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Mar 25 2009]
|
|
MATHEMATICA
|
Table[4^n, {n, 0, 30}] - Stefan Steinerberger (stefan.steinerberger(AT)gmail.com), Apr 01 2006
a = 1; lst = {a}; Do[a = a + 3*a; AppendTo[lst, a], {n, 0, 25}]; lst [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Jul 08 2009]
|
|
PROGRAM
|
(Other) sage: [lucas_number1(n, 4, 0) for n in xrange(1, 26)]# [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Apr 22 2009]
(PARI) A000302(n)=4^n [From Michael Porter (michael_b_porter(AT)yahoo.com), Nov 06 2009]
|
|
CROSSREFS
|
Cf. A024036, A052539.
a(n) = A159991(n)/A001024(n). [From Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), May 02 2009]
A032443 [From Gary W. Adamson (qntmpkt(AT)yahoo.com), May 15 2009]
Sequence in context: A006811 A005755 A077821 this_sequence A050734 A075614 A083592
Adjacent sequences: A000299 A000300 A000301 this_sequence A000303 A000304 A000305
|
|
KEYWORD
|
easy,nonn,nice,core,new
|
|
AUTHOR
|
N. J. A. Sloane (njas(AT)research.att.com).
|
|
EXTENSIONS
|
Removed attribute "conjectured" from Plouffe g.f R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Mar 11 2009
|
|
|
Search completed in 0.004 seconds
|