Search: id:A002411 Results 1-1 of 1 results found. %I A002411 M4116 N1709 %S A002411 0,1,6,18,40,75,126,196,288,405,550,726,936,1183,1470,1800,2176,2601, %T A002411 3078,3610,4200,4851,5566,6348,7200,8125,9126,10206,11368,12615,13950, %U A002411 15376,16896,18513,20230,22050,23976,26011,28158,30420,32800,35301 %N A002411 Pentagonal pyramidal numbers: n^2*(n+1)/2. %C A002411 a(n)=n^2(n+1)/2 is half the number of colorings of three points on a line with n+1 colors. - Ron Hardin (rhhardin(AT)att.net), Feb 23 2002 %C A002411 a(n) = number of (n+6)-bit binary sequences with exactly 7 1's none of which is isolated. A 1 is isolated if its immediate neighbor(s) are 0. - David Callan (callan(AT)stat.wisc.edu), Jul 15 2004 %C A002411 Also as a(n)=(1/6)*(3*n^3+3*n^2), n>0: structured trigonal prism numbers (Cf. A100177 - structured prisms; A100145 for more on structured numbers). - James A. Record (james.record(AT)gmail.com), Nov. 7, 2004. %C A002411 Kekule numbers for certain benzenoids. - Emeric Deutsch (deutsch(AT)duke.poly.edu), Nov 18 2005 %C A002411 If Y is a 3-subset of an n-set X then, for n>=5, a(n-4) is the number of 5-subsets of X having at least two elements in common with Y. - Milan R. Janjic (agnus(AT)blic.net), Nov 23 2007 %C A002411 a(n-1), n>=2, is the number of ways to have n identical objects in m=2 of alltogether n distinguishable boxes (n-2 boxes stay empty). W. Lang, Nov 13 2007. %C A002411 a(n+1) is the convolution of (n+1) and (3n+1). [From Paul Barry (pbarry(AT)wit.ie), Sep 18 2008] %C A002411 A002411[n+1]=denom(2/((n+2)*(n+1)^2)) [From Stephen Crowley (crow(AT)crowlogic.net), Jun 28 2009] %D A002411 N. J. A. Sloane and Simon Plouffe, The Encyclopedia of Integer Sequences, Academic Press, 1995 (includes this sequence). %D A002411 N. J. A. Sloane, A Handbook of Integer Sequences, Academic Press, 1973 (includes this sequence). %D A002411 A. H. Beiler, Recreations in the Theory of Numbers, Dover, NY, 1964, p. 194. %D A002411 L. E. Dickson, History of the Theory of Numbers. Carnegie Institute Public. 256, Washington, DC, Vol. 1, 1919; Vol. 2, 1920; Vol. 3, 1923, see vol. 2, p. 2. %D A002411 L. Hogben, Choice and Chance by Cardpack and Chessboard. Vol. 1, Chanticleer Press, NY, 1950, p. 36. %D A002411 S. M. Losanitsch, Die Isomerie-Arten bei den Homologen der Paraffin-Reihe, Chem. Ber. 30 (1897), 1917-1926. %D A002411 S. J. Cyvin and I. Gutman, Kekule structures in benzenoid hydrocarbons, Lecture Notes in Chemistry, No. 46, Springer, New York, 1988 (see p. 166, Table 10.4/I/5). %H A002411 T. D. Noe, Table of n, a(n) for n=0..1000 %H A002411 Index entries for two-way infinite sequences %H A002411 Index entries for sequences related to linear recurrences with constant coefficients %H A002411 P. Chinn and S. Heubach, Integer Sequences Related to Compositions without 2's, J. Integer Seqs., Vol. 6, 2003. %H A002411 S. Plouffe, Approximations de S\'{e}ries G\'{e}n\'{e}ratrices et Quelques Conjectures, Dissertation, Universit\'{e} du Qu\'{e}bec \`{a} Montr\'{e}al, 1992. %H A002411 S. Plouffe, 1031 Generating Functions and Conjectures, Universit\'{e} du Qu\'{e}bec \`{a} Montr\'{e}al, 1992. %H A002411 Eric Weisstein's World of Mathematics, Link to a section of The World of Mathematics. %H A002411 Eric Weisstein's World of Mathematics, Wiener Index %F A002411 Average of n^2 and n^3. %F A002411 a(n) = sum of n smallest multiples of n. - Amarnath Murthy (amarnath_murthy(AT)yahoo.com), Sep 20 2002 %F A002411 G.f.: x(1+2x)/(1-x)^4 - Paul Barry (pbarry(AT)wit.ie), Mar 21 2003 %F A002411 a(n)=sum{k=0..n, n(n-k)}. - Paul Barry (pbarry(AT)wit.ie), Jul 21 2003 %F A002411 a(n) = whole numbers * triangular numbers - Xavier Acloque Oct 27 2003 %F A002411 a(n) = (1/2)*Sum[Sum[(i+j),{i, 1, n}],{j, 1, n}] = (1/2)*(n^2+n^3) = (1/2)*A011379(n). - Alexander Adamchuk (alex(AT)kolmogorov.com), Apr 13 2006 %F A002411 sum (n*j,j=0..n). - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Sep 12 2006 %F A002411 a(n)=sum(sum(k, j=1..n),k=1..n), n>=0 . - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), May 11 2007 %F A002411 Row sums of triangle A127739, triangle A132118; and binomial transform of [1, 5, 7, 3, 0, 0, 0,...] = (1, 6, 18, 40, 75,...). - Gary W. Adamson (qntmpkt(AT)yahoo.com), Aug 10 2007 %F A002411 G.f.: x*F(2,3;1;x); [From Paul Barry (pbarry(AT)wit.ie), Sep 18 2008] %F A002411 sum(1/A002411[j],j=1..infinity)=hypergeom([1, 1, 1], [ 2, 3], 1)=-2+2*Zeta(2) [From Stephen Crowley (crow(AT)crowlogic.net), Jun 28 2009] %e A002411 a(3)=18 because 4 identical balls can be put into m=2 of n=4 distinguishable boxes in binomial(4,2)*(2!/(1!*1!)+ 2!/(2!) ) = 6*(2+1) =18 ways. The m=2 part partitions of 4, namely (1,3) and (2^2) specify the filling of each of the 6 possible two box choices. W. Lang, Nov 13 2007. %p A002411 Epi:=(r,n)->stirling2(r,n): [seq (Epi(n+1,n),n=0..41)]; - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Dec 05 2006 %p A002411 seq((n-1)*binomial(n,2), n=1..42); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Feb 28 2007 %p A002411 a:=n->sum(sum(k, j=1..n),k=1..n): seq(a(n), n=0..41); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), May 11 2007 %p A002411 A002411:=(1+2*z)/(z-1)**4; [S. Plouffe in his 1992 dissertation.] %p A002411 a:=n->(sum((numbcomp(n,3)), j=3..n)):seq(a(n), n=2..37); [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Aug 24 2008] %t A002411 lst={};Do[s0=n^2;s1=n^3;AppendTo[lst,(s1+s0)/2],{n,0,5!}];lst [From Vladimir Orlovsky (4vladimir(AT)gmail.com), Feb 19 2009] %t A002411 Table[Sum[Binomial[n, 2], {i, 2, n}], {n, 1, 41}] [From Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Jul 10 2009] %o A002411 (PARI) a(n)=n^2*(n+1)/2 %Y A002411 Cf. A015223, A015224, A014799, A014800. %Y A002411 Cf. A011379, A127739, A132118. %Y A002411 A006002(n)=-a(-1-n). %Y A002411 a(n)= A093560(n+2, 3), (3, 1)-Pascal column. %Y A002411 A row or column of A132191. %Y A002411 Second column of triangle A103371. %Y A002411 Sequence in context: A129863 A035489 A122061 this_sequence A023658 A059834 A015224 %Y A002411 Adjacent sequences: A002408 A002409 A002410 this_sequence A002412 A002413 A002414 %K A002411 nonn,easy,nice %O A002411 0,3 %A A002411 N. J. A. Sloane (njas(AT)research.att.com). %E A002411 zeta hypergeometric formula [From Stephen Crowley (crow(AT)crowlogic.net), Jun 28 2009] Search completed in 0.002 seconds