Search: id:A103314 Results 1-1 of 1 results found. %I A103314 %S A103314 1,1,2,2,4,2,10,2,16,8,34,2,100,2,130,38,256,2,1000,2,1156,134,2050,2, %T A103314 10000,32,8194,512,16900,2,146854,2,65536,2054,131074,158,1000000,2, %U A103314 524290,8198,1336336,2,11680390,2,4202500,54872,8388610,2,100000000,128 %N A103314 Total number of subsets of the n-th roots of 1 that add to zero. %C A103314 The term a(0) = 1 counts the single zero-sum subset of the (by convention) empty set of zeroth roots of 1. %C A103314 Comment from David W. Wilson, May 19 2005: I am inclined to believe that if S is a zero-sum subset of the n-th roots of 1, that n can be built up from (zero-sum) cyclically balanced subsets via the following operations: 1. A U B, where A and B are disjoint. 2. A - B, where B is a subset of A. %C A103314 Lam and Leung's paper, though interesting, does not apply directly to this sequence because it allows repetitions of the roots in the sums. %C A103314 Observe that 2^n=a(n) (mod n). Sequence A107847 is the quotient (2^n-a(n))/ n. - T. D. Noe (noe(AT)sspectra.com), May 25 2005 %C A103314 Comment from Max Alekseyev, Jan 31 2008 (Start): Every subset of the set U(n) = { 1=r^0, r^1, ..., r^(n-1) } of the n-th power roots of 1 (where r is a fixed primitive root) defines a binary word w of the length n where the j-th bit is 1 iff the root r^j is included in the subset. %C A103314 If d is the period of w with respect to cyclic rotations (thus d|n) then the periodic part of w uniquely defines some binary Lyndon word of the length d (see A001037). In turn, each binary Lyndon word of the length d, where dTable of n, a(n) for n = 0..164 %H A103314 T. Y. Lam and K. H. Leung, On vanishing sums for roots of unity %H A103314 T. D. Noe, Sums of Roots of Unity Plots %H A103314 T. D. Noe, Proof a(n)=a(s(n))^(n/ s(n)) %H A103314 Sasha Rybak, in: Zero sums of roots of unity on forum.mexmat.ru. %F A103314 a(n) = A070894(n)+1. %F A103314 a(2^n) = 2^(2^(n-1)). - Dan Asimov and Gareth McCaughan, Mar 11 2005 %F A103314 a(2n) = a(n)^2 if n is even. If p, q are primes, a(pq) = 2^p+2^q-2. In particular, if p is prime, a(2p) = 2^p + 2. - Gareth McCaughan, Mar 12 2005 %F A103314 a(n) == 2^n (mod n), a(p) = 2 (p prime). - David W. Wilson (davidwwilson(AT)comcast.net), May 08 2005 %F A103314 It appears that a(n) = a(s(n))^(n/s(n)) where s(n) = A007947(n) is the squarefree kernel of n. This is true if all zero-sum subsets of the n-th roots of 1 are formed by set operations on cyclic subsets. If true, A103314 is determined by its values on squarefree numbers (A005117). Some consequences would be a(p^n) = 2^p^(n-1), a(p^m q^n) = (2^p+2^q+2)^(p^(m-1) q^(n-1)) and a(p^2 n) = a(pn)^p for primes p and q. - David W. Wilson (davidwwilson(AT)comcast.net), May 08 2005 %F A103314 a(pn) = a(n)^p when p is prime and p|n; a(2p) = 2^p+2 when p is an odd prime. More generally a(pq) = 2^p+2^q-2 when p, q are distinct primes. - Gareth McCaughan (gareth.mccaughan(AT)pobox.com), Mar 12 2005 %F A103314 For distinct odd primes p and q, a(2pq) = (2^p+2)^q + (2^q+2)^p - 2(2^p+1)^q - 2(2^q+1)^p + 2^(pq) + SUM[j=0..p] binomial(p,j)(2^j+2^(p-j))^q. - Sasha Rybak, Sep 21 2007. %F A103314 a(n) = n*A110981(n) + 2^n - n*A001037(n). - Max Alekseyev, Jan 14 2008 %t A103314 Table[Plus@@Table[Count[(KSubsets[Range[n], k]), q_List/;Chop[Abs[Plus@@(E^(2.*Pi*I*q/ n))]]==0], {k, 0, n}], {n, 15}] (T. D. Noe) %t A103314 Needs["DiscreteMath`Combinatorica`"]; Table[Plus@@Table[Count[(KSubsets[Range[n], k]), q_List/;Chop[Abs[Plus@@(E^(2.*Pi*I*q/n))]]==0], {k, 0, n}], {n, 15}] (T. D. Noe) %o A103314 (PARI program from Max Alekseyev and M. F. Hasler that implements all known results, Jan 31 2008) %o A103314 /* works for all n except for 165, 195, 210, 231, 255, 273, 285, 330, 345, ... */ %o A103314 A103314(n) = { local(f=factor(n)); n<2 & return(1); n==f[1,1] & return(2); %o A103314 vecmax(f[,2])>1 & return(A103314(f=prod(i=1,#f~,f[i,1]))^(n/f)); %o A103314 if( 2==#f=f[,1], return(2^f[1]+2^f[2]-2)); %o A103314 #f==3 & f[1]==2 & return(sum(j=0,f[2],binomial(f[2],j)*(2^j+2^(f[2]-j))^f[3]) %o A103314 +(2^f[2]+2)^f[3]+(2^f[3]+2)^f[2]-2*((2^f[2]+1)^f[3]+(2^f[3]+1)^f[2])+2^(f[2]*f[3])); %o A103314 n==105 & return(166093023482); error("A103314(n) is unknown for n=",n) } %Y A103314 Equals A070894 + 1. A107847(n) = (2^n - A103314(n))/n, A110981 = A001037 - A107847. %Y A103314 Row sums of A103306. See also A006533, A006561, A006600, A007569, A007678. %Y A103314 Cf. A070925, A107753 (number of primitive subsets of the n-th roots of unity summing to zero), A107754 (number of subsets of the n-th roots of unity summing to one), A107861 (number of unique values in the sums of all subsets of the n-th roots of unity). %Y A103314 Sequence in context: A103178 A087909 A076078 this_sequence A111741 A111793 A064482 %Y A103314 Adjacent sequences: A103311 A103312 A103313 this_sequence A103315 A103316 A103317 %K A103314 nonn,nice,hard %O A103314 0,3 %A A103314 Wouter Meeussen (wouter.meeussen(AT)pandora.be), Mar 11 2005 %E A103314 More terms from David W. Wilson, Mar 12, 2005 %E A103314 Scott Huddleston (scotth(AT)ichips.intel.com) finds that a(30) >= 146854 and conjectures that is the true value of a(30). - Mar 24 2005. Confirmed by Meeussen and Wilson. %E A103314 More terms from T. D. Noe (noe(AT)sspectra.com), May 25 2005 %E A103314 Further terms from Max Alekseyev (maxale(AT)gmail.com) and M. F. Hasler (Maximilian.Hasler(AT)gmail.com), Jan 07 2008 %E A103314 Edited by M. F. Hasler (Maximilian.Hasler(AT)gmail.com), Feb 06 2008 Search completed in 0.002 seconds