%I A104101
%S A104101 4,8,15,16,23,42,108
%N A104101 The Lost Numbers.
%C A104101 These numbers were central to the plot of the TV-series "Lost", episodes
18 and 201.
%C A104101 Another number in the sequence, perhaps the next one, is 540: the number
of days which the team of two people who are addressed by the orientation
film are to stay at station 3. 4+8+15+16+23+42 = 108 * 5 = 540 -
Joshua Walton (joshuawalton<nospam>(AT)hotmail.com), May 05 2006
%C A104101 According to the show, 108 is not officially a part of the sequence,
it just happens to be the sum of those numbers. - Ville Saalo (vsaalo(AT)iki.fi),
Nov 19 2006
%C A104101 For n = 0,1,2,3,4,5 (1/120)(42n^5 - 305n^4 + 1100n^3 - 895n^2 + 1018n
+ 480) gives 4,12,35,89,213,511 -- the binomial transform of 4,8,
15,16,23,42. The sequence continues 1194,2622,5346,10150,18093....
The polynomial (1/120)(42x^5 - 305x^4 + 1100x^3 - 895x^2 + 1018x
+ 480) is the "Shaw-Basho polynomial". - Ross La Haye (rlahaye(AT)new.rr.com),
Feb 26 2007
%H A104101 Dicander, M., "The Lost Numbers" <a href="http://www.d.kth.se/~dicander/
lost.html">The Lost Numbers: 4 8 15 16 23 42</a>
%H A104101 Lostpedia contributors, <a href="http://www.lostpedia.com/index.php?title=The_Numbers&oldid=148826">
"The Numbers", Lostpedia</a>
%H A104101 Wikipedia contributors, <a href="http://en.wikipedia.org/w/index.php?title=Mythology_of_Lost&oldid=88596321">
"Mythology of Lost", Wikipedia, The Free Encyclopedia</a>
%H A104101 Shaw, Doug, <a href="http://www.dougshaw.com/lost/">The Lost Sequence</
a>
%F A104101 a(n) = (1/40)(-9n^5 + 125n^4 - 585n^3 + 1075n^2 - 446n + 160) for n =
0,1,2,3,4,5. The sequence continues 46,-52,-426,-1364,-3295... -
Ross La Haye (rlahaye(AT)new.rr.com), Feb 26 2007
%Y A104101 Sequence in context: A112312 A076343 A130826 this_sequence A136403 A071422
A113902
%Y A104101 Adjacent sequences: A104098 A104099 A104100 this_sequence A104102 A104103
A104104
%K A104101 nonn,unkn
%O A104101 0,1
%A A104101 Marcus Dicander (dicander(AT)kth.se), Mar 04 2005
%E A104101 a(7) from Kraig B Helberg (bethplease(AT)gmail.com), Dec 24 2005
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