Logo

Greetings from The On-Line Encyclopedia of Integer Sequences!

Hints

Search: id:A000188
Displaying 1-1 of 1 results found. page 1
     Format: long | short | internal | text      Sort: relevance | references | number      Highlight: on | off
A000188 (1) Number of solutions to x^2 = 0 (mod n). (2) Also square root of largest square dividing n. (3) Also Max_{ d divides n } GCD[d,n/d]. +0
68
1, 1, 1, 2, 1, 1, 1, 2, 3, 1, 1, 2, 1, 1, 1, 4, 1, 3, 1, 2, 1, 1, 1, 2, 5, 1, 3, 2, 1, 1, 1, 4, 1, 1, 1, 6, 1, 1, 1, 2, 1, 1, 1, 2, 3, 1, 1, 4, 7, 5, 1, 2, 1, 3, 1, 2, 1, 1, 1, 2, 1, 1, 3, 8, 1, 1, 1, 2, 1, 1, 1, 6, 1, 1, 5, 2, 1, 1, 1, 4, 9, 1, 1, 2, 1, 1, 1, 2, 1, 3 (list; graph; listen)
OFFSET

1,4

COMMENT

Shadow transform of the squares A000290. - Vladeta Jovovic (vladeta(AT)eunet.rs), Aug 02 2002

Labos Elemer (LABOS(AT)ana.sote.hu) and Henry Bottomley (se16(AT)btinternet.com) independently proved that (2) and (3) define the same sequence. Bottomley also showed that (1) and (2) define the same sequence.

Labos: Proof that (2)=(3): Let Max{[GCD[d,n/d]}=K, then d=Kx,n/d=Ky so n=KKxy where xy is the square-free part of n,otherwise K is not maximal. Observe also that g=GCD[K,xy] is not necessarily 1. Thus K is also the "maximal square-root factor" of n.

A note on square roots of numbers: we can write sqrt(n) = b*sqrt(c) where c is squarefree. Then b = A000188(n) is the "inner square root" of n, c = A007913(n), LCM(b,c) = A007947(n) = "squarefree kernel" of n and bc = A019554(n) = "outer square root" of n.

REFERENCES

Gerry Myerson, Trifectas in Geometric Progression, Australian Mathematical Society Gazette, 2008, to appear.

LINKS

T. D. Noe, Table of n, a(n) for n=1..10000

H. Bottomley, Some Smarandache-type multiplicative sequences

Kevin A. Broughan, Restricted divisor sums, Acta Arithmetica, vol. 101, (2002), pp. 105-114.

S. R. Finch and Pascal Sebah, Squares and Cubes Modulo n (arXiv:math.NT/0604465).

N. J. A. Sloane, Transforms

FORMULA

a(n) = Sum_{d^2|n} phi(d), where phi = Euler totient function A000010.

Multiplicative with a(p^e) = p^[e/2]. - David W. Wilson (davidwwilson(AT)comcast.net), Aug 01, 2001.

Dirichlet series: Sum(n=1..inf, a(n)/n^s) = zeta(2*s-1)*zeta(s)/zeta(2*s), (Re(s)>1).

MAPLE

with(numtheory):A000188 := proc(n) local i: RETURN(op(mul(i, i=map(x->x[1]^floor(x[2]/2), ifactors(n)[2])))); end;

MATHEMATICA

Array[ Function[ n, Count[ Array[ PowerMod[ #, 2, n ]&, n, 0 ], 0 ] ], 100 ]

PROGRAM

(PARI) a(n)=if(n<1, 0, sum(i=1, n, i*i%n==0))

(PARI) a(n)=sqrtint(n/core(n)) [From Zak Seidov (zakseidov(AT)yahoo.com), Apr 07 2009]

CROSSREFS

a(n) = n/A019554(n)

Cf. A008833, A007913, A117811, A046951, A055210.

Cf. A007913, A007947, A019554. For partial sums see A120486.

Sequence in context: A046854 A066170 A071773 this_sequence A162401 A097886 A088863

Adjacent sequences: A000185 A000186 A000187 this_sequence A000189 A000190 A000191

KEYWORD

nonn,easy,nice,mult

AUTHOR

N. J. A. Sloane (njas(AT)research.att.com).

page 1

Search completed in 0.003 seconds

Lookup | Welcome | Find friends | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Transforms | Puzzles | Hot | Classics
More pages | Superseeker | Maintained by N. J. A. Sloane (njas@research.att.com)

Last modified November 24 23:16 EST 2009. Contains 167481 sequences.


AT&T Labs Research