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A025172 Let phi = arccos(1/3), the dihedral angle of the regular tetrahedron. Then cos(n*phi) = a(n)/3^n. +0
3
1, 1, -7, -23, 17, 241, 329, -1511, -5983, 1633, 57113, 99529, -314959, -1525679, -216727, 13297657, 28545857, -62587199, -382087111, -200889431, 3037005137, 7882015153, -11569015927, -94076168231, -84031193119, 678623127841, 2113526993753 (list; graph; listen)
OFFSET

0,3

COMMENT

Used when showing that the regular simplex is not "scisssors-dissectable" to a cube, thus answering Hilbert's third problem.

REFERENCES

J. L. Dupont, Scissors Congruences, Group Homology and Characteristic Classes, World Scientific, 2001. See p. 4.

FORMULA

a(0) = 1, a(1) = 1; for n >= 2, a(n) = 2*a(n-1) - 9*a(n-2). - Warut Roonguthai (warut822(AT)yahoo.com), Oct 11 2005

a(n) = (1/2)*(1-2*i*2^(1/2))^(n+1)+(1/2)*(1+2*i*2^(1/2))^(n+1), where i=sqrt(-1). - Vladeta Jovovic (vladeta(AT)eunet.rs), Apr 19 2003

a(n) is the permanent of the matrix M^n, where M = [i, 2; 1, i]. - Simone Severini (simoseve(AT)gmail.com), Apr 27 2007

MAPLE

f:=proc(n) option remember; if n <= 1 then RETURN(1); fi; 2*f(n-1)-9*f(n-2); end;

MATHEMATICA

Table[ n/2 3^n GegenbauerC[ n, 1/3 ], {n, 24} ]

PROGRAM

(PARI) {a(n)= if(n<0, 0, 3^(n-1)* subst(3* poltchebi(abs(n)), x, 1/3))} /* Michael Somos Mar 14 2007 */

CROSSREFS

Sequence in context: A070411 A167224 A121815 this_sequence A115023 A009228 A031450

Adjacent sequences: A025169 A025170 A025171 this_sequence A025173 A025174 A025175

KEYWORD

sign

AUTHOR

Wouter Meeussen (wouter.meeussen(AT)pandora.be)

EXTENSIONS

Better description from Vladeta Jovovic (vladeta(AT)eunet.rs), Apr 19 2003

Edited by N. J. A. Sloane (njas(AT)research.att.com), Feb 22 2007. Among other things, I changed the offset and the beginning of the sequence, so some of the formulae may need to be adjusted slightly.

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Last modified November 25 08:46 EST 2009. Contains 167481 sequences.


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