1,2

The reason is that we obtain the same Diophantine equation with various parameters is the following: the number which is written 361 in base 4*A046179(n)-2 is the square of 6*A046178(n)-1. That is, 361 in base 110770 is 3*110770^2+6*110770+1=36810643321 i.e. the square of 191861 if we consider the third terms of A046179 and A046178 which are 27693 and 31977 respectively. - Richard Choulet (richardchoulet(AT)yahoo.fr), Oct 03 2007

Eric Weisstein's World of Mathematics, Link to a section of The World of Mathematics.

a(n) = 194*a(n-1) - a(n-2) - 32; g.f.: (1-30*x-3*x^2)/((1-x)*(1-194*x+x^2)) - Warut Roonguthai (warut822(AT)yahoo.com) Jan 08 2001

a(n+1)=97*a(n)-16+28*(12*a(n)^2-4*a(n)+1)^0.5 - R. Choulet (richardchoulet(AT)yahoo.fr), Oct 09 2007

a(n)=(1/6)+(5/12)*[97-56*sqrt(3)]^n+(5/12)*[97+56*sqrt(3)]^n-(1/4)*[97-56*sqrt(3)]^n*sqrt(3) +(1/4)*sqrt(3)*[97+56*sqrt(3)]^n, with n>=0 [From Paolo P. Lava (ppl(AT)spl.at), Sep 26 2008]

Cf. A046179, A046180.

Cf. A046179 A046180.

Adjacent sequences: A046175 A046176 A046177 this_sequence A046179 A046180 A046181

Sequence in context: A071576 A140912 A132055 this_sequence A015982 A065210 A038007

nonn,easy

Eric Weisstein (eric(AT)weisstein.com)