|
Search: id:A051869
|
|
| |
|
| 0, 1, 17, 48, 94, 155, 231, 322, 428, 549, 685, 836, 1002, 1183, 1379, 1590, 1816, 2057, 2313, 2584, 2870, 3171, 3487, 3818, 4164, 4525, 4901, 5292, 5698, 6119, 6555, 7006, 7472, 7953, 8449, 8960, 9486, 10027, 10583, 11154, 11740, 12341
(list; graph; listen)
|
|
|
OFFSET
|
0,3
|
|
|
REFERENCES
|
A. H. Beiler, Recreations in the Theory of Numbers, Dover, N.Y., 1964, p. 189.
|
|
FORMULA
|
a(n)=n(15n-13)/2.
a(n)=15*n+a(n-1)-29 (with a(1)=0) [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Nov 13 2009]
|
|
EXAMPLE
|
For n=2, a(2)=15*2+0-29=1; n=3, a(3)=15*3+1-29=17; n=4, a(4)=15*4+17-29=48 [From Vincenzo Librandi (vincenzo.librandi(AT)tin.it), Nov 13 2009]
|
|
MAPLE
|
a[0]:=0:a[1]:=1:for n from 2 to 50 do a[n]:=2*a[n-1]-a[n-2]+15 od: seq(a[n], n=0..41); - Zerinvary Lajos (zerinvarylajos(AT)yahoo.com), Feb 18 2008
|
|
MATHEMATICA
|
s=0; lst={s}; Do[s+=n++ +1; AppendTo[lst, s], {n, 0, 6!, 15}]; lst [From Vladimir Orlovsky (4vladimir(AT)gmail.com), Nov 16 2008]
|
|
CROSSREFS
|
Cf. A000217, A002378, A051868, A051871, A051870, A051871.
Sequence in context: A083296 A159850 A031122 this_sequence A029487 A069129 A124710
Adjacent sequences: A051866 A051867 A051868 this_sequence A051870 A051871 A051872
|
|
KEYWORD
|
nonn,new
|
|
AUTHOR
|
N. J. A. Sloane (njas(AT)research.att.com), Dec 15 1999
|
|
|
Search completed in 0.002 seconds
|
