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Search: id:A054643
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| A054643 |
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Primes p(n) such that Mod[p(n)+p(n+1)+p(n+2),3]=0 |
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+0
3
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| 3, 47, 151, 167, 199, 251, 257, 367, 503, 523, 557, 587, 601, 647, 727, 941, 971, 991, 1063, 1097, 1117, 1181, 1217, 1231, 1361, 1453, 1493, 1499, 1531, 1741, 1747, 1753, 1759, 1889, 1901, 1907, 2063, 2161, 2281, 2393, 2399, 2411, 2441, 2671, 2897, 2957
(list; graph; listen)
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OFFSET
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1,1
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COMMENT
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The 2 differences of these 3 primes should be congruent of 6, except the first prime 3, for which 3+5+7=15 holds. Sequences like A047948, A052198 etc. are subsequences here.
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EXAMPLE
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For p(242)=1531, the sum is 4623, the mean is 1541 and the successive differences are 6a=12 or 6b=6 resp.
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CROSSREFS
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A034961, A034707, A024675, A052288, A047948, A052198.
Sequence in context: A139845 A141850 A003551 this_sequence A122535 A058427 A142293
Adjacent sequences: A054640 A054641 A054642 this_sequence A054644 A054645 A054646
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KEYWORD
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nonn
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AUTHOR
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Labos E. (labos(AT)ana.sote.hu), May 15 2000
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