|
Search: id:A059022
|
|
|
| A059022 |
|
Triangle of Stirling numbers of order 3. |
|
+0 6
|
|
| 1, 1, 1, 1, 10, 1, 35, 1, 91, 1, 210, 280, 1, 456, 2100, 1, 957, 10395, 1, 1969, 42735, 15400, 1, 4004, 158301, 200200, 1, 8086, 549549, 1611610, 1, 16263, 1827826, 10335325, 1401400, 1, 32631, 5903898, 57962905, 28028000, 1, 65382, 18682014
(list; graph; listen)
|
|
|
OFFSET
|
3,5
|
|
|
COMMENT
|
The number of partitions of the set N, |N|=n, into k blocks, all of cardinality greater than or equal to 3. This is the 3-associated Stirling number of the second kind (Comtet) or the Stirling number of order 3 (Fekete).
This is entered as a triangular array. The entries S_3(n,k) are zero for 3k>n, so these values are omitted. Initial entry in sequence is S_3(3,1).
Rows are of lengths 1,1,1,2,2,2,3,3,3,...
|
|
REFERENCES
|
L. Comtet, Advanced Combinatorics, Reidel, 1974, p. 222.
A. E. Fekete, Apropos two notes on notation, Amer. Math. Monthly, 101 (1994), 771-778.
J. Riordan, An Introduction to Combinatorial Analysis, Wiley, 1958, p. 76.
|
|
FORMULA
|
S_r(n+1, k)=k S_r(n, k)+binomial(n, r-1)S_r(n-r+1, k-1) for this sequence, r=3 G.f.: sum(S_r(n, k)u^k ((t^n)/(n!)), n=0..infty, k=0..infty)=exp(u(e^t-sum(t^i/i!, i=0..r-1)))
|
|
EXAMPLE
|
There are 10 ways of partitioning a set N of cardinality 6 into 2 blocks each of cardinality at least 3, so S_3(6,2)=10.
|
|
CROSSREFS
|
Cf. A008299, A059023, A059024, A059025.
Sequence in context: A050999 A070246 A085044 this_sequence A115097 A050313 A116574
Adjacent sequences: A059019 A059020 A059021 this_sequence A059023 A059024 A059025
|
|
KEYWORD
|
nonn,tabf,nice
|
|
AUTHOR
|
Barbara Haas Margolius (margolius(AT)math.csuohio.edu), Dec 14 2000
|
|
|
Search completed in 0.002 seconds
|