|
Search: id:A073184
|
|
|
| A073184 |
|
Number of cube-free divisors of n. |
|
+0 4
|
|
| 1, 2, 2, 3, 2, 4, 2, 3, 3, 4, 2, 6, 2, 4, 4, 3, 2, 6, 2, 6, 4, 4, 2, 6, 3, 4, 3, 6, 2, 8, 2, 3, 4, 4, 4, 9, 2, 4, 4, 6, 2, 8, 2, 6, 6, 4, 2, 6, 3, 6, 4, 6, 2, 6, 4, 6, 4, 4, 2, 12, 2, 4, 6, 3, 4, 8, 2, 6, 4, 8, 2, 9, 2, 4, 6, 6, 4, 8, 2, 6, 3, 4, 2, 12, 4, 4, 4, 6, 2, 12, 4, 6, 4, 4, 4, 6, 2, 6, 6, 9, 2, 8, 2
(list; graph; listen)
|
|
|
OFFSET
|
1,2
|
|
|
COMMENT
|
a(n) = sum of divisors of the cube-free kernel of n: a(n)=A073184(A007948(n));
a(n) <= A073182(n).
Multiplicative because it is the Inverse Moebius transform of the characteristic function of cube-free numbers. a(n) is a prime signature sequence. a(p) = 2, a(p^e) = 3, e>1. Christian G. Bower (bowerc(AT)usa.net) May 18, 2005.
Multiplicative because it is the Dirichlet convolution of a(n)=n with characteristic function of cube-free numbers, both multiplicative sequences. a(p) = 1+p, a(p^e) = 1+p+p^2, e>1. Christian G. Bower (bowerc(AT)usa.net) May 18, 2005.
|
|
EXAMPLE
|
The divisors of 56 are {1, 2, 4, 7, 8, 14, 28, 56}, 8=2^3 and 56=7*2^3 are not cube-free, therefore a(56)=6.
|
|
CROSSREFS
|
Cf. A000005, A073185, A004709, A073183, A073180, A034444.
Sequence in context: A111336 A083902 A106491 this_sequence A073182 A049599 A043261
Adjacent sequences: A073181 A073182 A073183 this_sequence A073185 A073186 A073187
|
|
KEYWORD
|
nonn,mult
|
|
AUTHOR
|
Reinhard Zumkeller (reinhard.zumkeller(AT)gmail.com), Jul 19 2002
|
|
|
Search completed in 0.002 seconds
|