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Search: id:A154325
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| A154325 |
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Triangle with interior all 2's and borders 1. |
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+0 5
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| 1, 1, 1, 1, 2, 1, 1, 2, 2, 1, 1, 2, 2, 2, 1, 1, 2, 2, 2, 2, 1, 1, 2, 2, 2, 2, 2, 1, 1, 2, 2, 2, 2, 2, 2, 1, 1, 2, 2, 2, 2, 2, 2, 2, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 1
(list; table; graph; listen)
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OFFSET
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0,5
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COMMENT
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This triangle follows a general construction method as follows: Let a(n) be an integer sequence
with a(0)=1, a(1)=1. Then T(n,k,r):=[k<=n](1+r*a(k)*a(n-k)) defines a symmetrical triangle.
Row sums are n+1+r*sum{k=0..n, a(k)*a(n-k)} and central coefficients are 1+r*a(n)^2.
Here a(n)=1-0^n and r=1. Row sums are A004277.
Eigensequence of the triangle = A000129, the Pell sequence. [From Gary W. Adamson (qntmpkt(AT)yahoo.com), Feb 12 2009]
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FORMULA
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Number triangle T(n,k)=[k<=n](2-0^(n-k)-0^k+0^(n+k))=[k<=n](2-0^(k(n-k))).
a(n) = 2 - A103451(n). [From Omar E. Pol (info(AT)polprimos.com), Jan 18 2009]
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EXAMPLE
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Triangle begins
1,
1, 1,
1, 2, 1,
1, 2, 2, 1,
1, 2, 2, 2, 1,
1, 2, 2, 2, 2, 1,
1, 2, 2, 2, 2, 2, 1
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CROSSREFS
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Cf. A129765. [From R. J. Mathar (mathar(AT)strw.leidenuniv.nl), Jan 14 2009]
Cf. A103451. [From Omar E. Pol (info(AT)polprimos.com), Jan 18 2009]
A000129 [From Gary W. Adamson (qntmpkt(AT)yahoo.com), Feb 12 2009]
Sequence in context: A023589 A134034 A157415 this_sequence A129765 A143187 A143209
Adjacent sequences: A154322 A154323 A154324 this_sequence A154326 A154327 A154328
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KEYWORD
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easy,nonn,tabl
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AUTHOR
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Paul Barry (pbarry(AT)wit.ie), Jan 07 2009
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